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5130511303 = 25719963079
BaseRepresentation
bin1001100011100110…
…10110001111000111
3111020112221222102011
410301303112033013
541001402330203
62205032355051
7241065424621
oct46163261707
914215858364
105130511303
1121a3049095
12bb2245a87
13639bc6008
14369555c11
1520063676d
hex131cd63c7

5130511303 has 4 divisors (see below), whose sum is σ = 5150474640. Its totient is φ = 5110547968.

The previous prime is 5130511291. The next prime is 5130511319. The reversal of 5130511303 is 3031150315.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5130511303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5130511103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9981283 + ... + 9981796.

It is an arithmetic number, because the mean of its divisors is an integer number (1287618660).

Almost surely, 25130511303 is an apocalyptic number.

5130511303 is a deficient number, since it is larger than the sum of its proper divisors (19963337).

5130511303 is a wasteful number, since it uses less digits than its factorization.

5130511303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19963336.

The product of its (nonzero) digits is 675, while the sum is 22.

The square root of 5130511303 is about 71627.5875832769. The cubic root of 5130511303 is about 1724.7264205776.

Adding to 5130511303 its reverse (3031150315), we get a palindrome (8161661618).

The spelling of 5130511303 in words is "five billion, one hundred thirty million, five hundred eleven thousand, three hundred three".

Divisors: 1 257 19963079 5130511303