Base | Representation |
---|---|
bin | 1110111011101000011… |
… | …11111110011111011001 |
3 | 1211001021102211020111112 |
4 | 13131310033332133121 |
5 | 31401212133002101 |
6 | 1031405333110105 |
7 | 52031615254034 |
oct | 7356417763731 |
9 | 1731242736445 |
10 | 513051453401 |
11 | 188647196623 |
12 | 83523a88335 |
13 | 394c4096576 |
14 | 1ab9074401b |
15 | d52b84a6bb |
hex | 77743fe7d9 |
513051453401 has 4 divisors (see below), whose sum is σ = 513283921152. Its totient is φ = 512818985652.
The previous prime is 513051453361. The next prime is 513051453419. The reversal of 513051453401 is 104354150315.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 513051453401 - 26 = 513051453337 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (513051413401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 116230565 + ... + 116234978.
It is an arithmetic number, because the mean of its divisors is an integer number (128320980288).
Almost surely, 2513051453401 is an apocalyptic number.
It is an amenable number.
513051453401 is a deficient number, since it is larger than the sum of its proper divisors (232467751).
513051453401 is a wasteful number, since it uses less digits than its factorization.
513051453401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 232467750.
The product of its (nonzero) digits is 18000, while the sum is 32.
The spelling of 513051453401 in words is "five hundred thirteen billion, fifty-one million, four hundred fifty-three thousand, four hundred one".
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