Base | Representation |
---|---|
bin | 100101010101000110001… |
… | …0100100100010101000111 |
3 | 200011110211111212000211212 |
4 | 1022222030110210111013 |
5 | 1133024324024401401 |
6 | 14524535004122035 |
7 | 1036445456153642 |
oct | 112521424442507 |
9 | 20143744760755 |
10 | 5130545153351 |
11 | 16a8940a93452 |
12 | 6aa40123631b |
13 | 2b2a67ba0237 |
14 | 13a4693dca59 |
15 | 8d6cd36bdbb |
hex | 4aa8c524547 |
5130545153351 has 4 divisors (see below), whose sum is σ = 5269208535912. Its totient is φ = 4991881770792.
The previous prime is 5130545153309. The next prime is 5130545153389. The reversal of 5130545153351 is 1533515450315.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5130545153351 - 238 = 4855667246407 is a prime.
It is a super-2 number, since 2×51305451533512 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5130545153299 and 5130545153308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5130545453351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69331691225 + ... + 69331691298.
It is an arithmetic number, because the mean of its divisors is an integer number (1317302133978).
Almost surely, 25130545153351 is an apocalyptic number.
5130545153351 is a deficient number, since it is larger than the sum of its proper divisors (138663382561).
5130545153351 is a wasteful number, since it uses less digits than its factorization.
5130545153351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 138663382560.
The product of its (nonzero) digits is 337500, while the sum is 41.
The spelling of 5130545153351 in words is "five trillion, one hundred thirty billion, five hundred forty-five million, one hundred fifty-three thousand, three hundred fifty-one".
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