Base | Representation |
---|---|
bin | 100101010101010001111… |
… | …0101100111101111100111 |
3 | 200011111212000020202221112 |
4 | 1022222203311213233213 |
5 | 1133031131030202210 |
6 | 14525042100335235 |
7 | 1036461316540250 |
oct | 112524365475747 |
9 | 20144760222845 |
10 | 5130939694055 |
11 | 16a902376a74a |
12 | 6aa4b13a451b |
13 | 2b2acb84c986 |
14 | 13a4a5981b27 |
15 | 8d702d02d05 |
hex | 4aaa3d67be7 |
5130939694055 has 16 divisors (see below), whose sum is σ = 7036907192640. Its totient is φ = 3518263698432.
The previous prime is 5130939694007. The next prime is 5130939694057. The reversal of 5130939694055 is 5504969390315.
5130939694055 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5130939694055 - 214 = 5130939677671 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5130939693985 and 5130939694003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5130939694057) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 650084 + ... + 3268713.
It is an arithmetic number, because the mean of its divisors is an integer number (439806699540).
Almost surely, 25130939694055 is an apocalyptic number.
5130939694055 is a deficient number, since it is larger than the sum of its proper divisors (1905967498585).
5130939694055 is a wasteful number, since it uses less digits than its factorization.
5130939694055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3956218.
The product of its (nonzero) digits is 19683000, while the sum is 59.
The spelling of 5130939694055 in words is "five trillion, one hundred thirty billion, nine hundred thirty-nine million, six hundred ninety-four thousand, fifty-five".
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