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5131103771551 = 17412947216411
BaseRepresentation
bin100101010101010110110…
…0111100001101110011111
3200011112021102222202221211
41022222231213201232133
51133032000031142201
614525110241205251
71036465351301302
oct112525547415637
920145242882854
105131103771551
1116a90a834758a
126aa538330827
132b2b2683a354
1413a4bd692b39
158d712413651
hex4aaad9e1b9f

5131103771551 has 4 divisors (see below), whose sum is σ = 5134050989704. Its totient is φ = 5128156553400.

The previous prime is 5131103771441. The next prime is 5131103771561. The reversal of 5131103771551 is 1551773011315.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5131103771551 - 211 = 5131103769503 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5131103771561) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1473606465 + ... + 1473609946.

It is an arithmetic number, because the mean of its divisors is an integer number (1283512747426).

Almost surely, 25131103771551 is an apocalyptic number.

5131103771551 is a deficient number, since it is larger than the sum of its proper divisors (2947218153).

5131103771551 is a wasteful number, since it uses less digits than its factorization.

5131103771551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2947218152.

The product of its (nonzero) digits is 55125, while the sum is 40.

Adding to 5131103771551 its reverse (1551773011315), we get a palindrome (6682876782866).

The spelling of 5131103771551 in words is "five trillion, one hundred thirty-one billion, one hundred three million, seven hundred seventy-one thousand, five hundred fifty-one".

Divisors: 1 1741 2947216411 5131103771551