Base | Representation |
---|---|
bin | 100101010101011011011… |
… | …1100011111101010001111 |
3 | 200011112200100110100221110 |
4 | 1022222312330133222033 |
5 | 1133032310111404210 |
6 | 14525133551303103 |
7 | 1036502261405613 |
oct | 112526674375217 |
9 | 20145610410843 |
10 | 5131260263055 |
11 | 16a9178712a03 |
12 | 6aa58081aa93 |
13 | 2b2b5009cb84 |
14 | 13a4d638b343 |
15 | 8d721026420 |
hex | 4aab6f1fa8f |
5131260263055 has 16 divisors (see below), whose sum is σ = 8217419528160. Its totient is φ = 2734204437888.
The previous prime is 5131260263029. The next prime is 5131260263083. The reversal of 5131260263055 is 5503620621315.
It is not a de Polignac number, because 5131260263055 - 25 = 5131260263023 is a prime.
It is a super-3 number, since 3×51312602630553 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 154214212 + ... + 154247481.
It is an arithmetic number, because the mean of its divisors is an integer number (513588720510).
Almost surely, 25131260263055 is an apocalyptic number.
5131260263055 is a deficient number, since it is larger than the sum of its proper divisors (3086159265105).
5131260263055 is a wasteful number, since it uses less digits than its factorization.
5131260263055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 308462810.
The product of its (nonzero) digits is 162000, while the sum is 39.
The spelling of 5131260263055 in words is "five trillion, one hundred thirty-one billion, two hundred sixty million, two hundred sixty-three thousand, fifty-five".
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