Base | Representation |
---|---|
bin | 1001100011110010… |
… | …11100100011010011 |
3 | 111020122222012110110 |
4 | 10301321130203103 |
5 | 41002310010120 |
6 | 2205130532403 |
7 | 241115133633 |
oct | 46171344323 |
9 | 14218865413 |
10 | 5132110035 |
11 | 21a3a40258 |
12 | bb2897103 |
13 | 63a335900 |
14 | 3698506c3 |
15 | 2008502e0 |
hex | 131e5c8d3 |
5132110035 has 24 divisors (see below), whose sum is σ = 8891612784. Its totient is φ = 2526576000.
The previous prime is 5132110013. The next prime is 5132110051. The reversal of 5132110035 is 5300112315.
It is not a de Polignac number, because 5132110035 - 25 = 5132110003 is a prime.
It is a super-2 number, since 2×51321100352 = 52677106822695402450, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5132109993 and 5132110020.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1009716 + ... + 1014785.
It is an arithmetic number, because the mean of its divisors is an integer number (370483866).
Almost surely, 25132110035 is an apocalyptic number.
5132110035 is a deficient number, since it is larger than the sum of its proper divisors (3759502749).
5132110035 is a wasteful number, since it uses less digits than its factorization.
5132110035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2024535 (or 2024522 counting only the distinct ones).
The product of its (nonzero) digits is 450, while the sum is 21.
The square root of 5132110035 is about 71638.7467436443. The cubic root of 5132110035 is about 1724.9055508043.
The spelling of 5132110035 in words is "five billion, one hundred thirty-two million, one hundred ten thousand, thirty-five".
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