Base | Representation |
---|---|
bin | 10111010101101001011100… |
… | …10111000000010101101111 |
3 | 20201201021100120020210000122 |
4 | 23222310232113000111233 |
5 | 23211322102023040133 |
6 | 301052410554115155 |
7 | 13544562461215334 |
oct | 1352645627002557 |
9 | 221637316223018 |
10 | 51321342002543 |
11 | 15397293685708 |
12 | 590a50571babb |
13 | 2283774248192 |
14 | c95d753b098b |
15 | 5deebc53b498 |
hex | 2ead2e5c056f |
51321342002543 has 8 divisors (see below), whose sum is σ = 51351804834000. Its totient is φ = 51290880153408.
The previous prime is 51321342002509. The next prime is 51321342002569. The reversal of 51321342002543 is 34520024312315.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 51321342002543 - 210 = 51321342001519 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51321342002143) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 122364008 + ... + 122782706.
It is an arithmetic number, because the mean of its divisors is an integer number (6418975604250).
Almost surely, 251321342002543 is an apocalyptic number.
51321342002543 is a deficient number, since it is larger than the sum of its proper divisors (30462831457).
51321342002543 is a wasteful number, since it uses less digits than its factorization.
51321342002543 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 491161.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 51321342002543 its reverse (34520024312315), we get a palindrome (85841366314858).
The spelling of 51321342002543 in words is "fifty-one trillion, three hundred twenty-one billion, three hundred forty-two million, two thousand, five hundred forty-three".
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