Base | Representation |
---|---|
bin | 100101010110010010101… |
… | …1100010111110100100011 |
3 | 200011201110112210201102012 |
4 | 1022230211130113310203 |
5 | 1133100104203111230 |
6 | 14530041533543135 |
7 | 1036566232025066 |
oct | 112544534276443 |
9 | 20151415721365 |
10 | 5133114113315 |
11 | 16a9a3a108061 |
12 | 6aa9b9644aab |
13 | 2b30871959a6 |
14 | 13a6306808dd |
15 | 8d7cdb6a395 |
hex | 4ab25717d23 |
5133114113315 has 4 divisors (see below), whose sum is σ = 6159736935984. Its totient is φ = 4106491290648.
The previous prime is 5133114113287. The next prime is 5133114113329.
5133114113315 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5133114113315 - 28 = 5133114113059 is a prime.
It is a super-3 number, since 3×51331141133153 (a number of 39 digits) contains 333 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 513311411327 + ... + 513311411336.
It is an arithmetic number, because the mean of its divisors is an integer number (1539934233996).
Almost surely, 25133114113315 is an apocalyptic number.
5133114113315 is a deficient number, since it is larger than the sum of its proper divisors (1026622822669).
5133114113315 is a wasteful number, since it uses less digits than its factorization.
5133114113315 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1026622822668.
The product of its digits is 8100, while the sum is 32.
The spelling of 5133114113315 in words is "five trillion, one hundred thirty-three billion, one hundred fourteen million, one hundred thirteen thousand, three hundred fifteen".
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