Base | Representation |
---|---|
bin | 10111010101111111100111… |
… | …10100000011011101101111 |
3 | 20201202102002002012121112101 |
4 | 23222333303310003131233 |
5 | 23212020441113214123 |
6 | 301102100025315531 |
7 | 13545463441162264 |
oct | 1352776364033557 |
9 | 221672062177471 |
10 | 51333244663663 |
11 | 153a13413a3126 |
12 | 5910887935ba7 |
13 | 228492018b521 |
14 | c967840d126b |
15 | 5e0467480aad |
hex | 2eaff3d0376f |
51333244663663 has 8 divisors (see below), whose sum is σ = 51579360009216. Its totient is φ = 51087156015000.
The previous prime is 51333244663619. The next prime is 51333244663739. The reversal of 51333244663663 is 36636644233315.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 51333244663663 - 237 = 51195805710191 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51333244643663) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2814031 + ... + 10515952.
It is an arithmetic number, because the mean of its divisors is an integer number (6447420001152).
Almost surely, 251333244663663 is an apocalyptic number.
51333244663663 is a deficient number, since it is larger than the sum of its proper divisors (246115345553).
51333244663663 is a wasteful number, since it uses less digits than its factorization.
51333244663663 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13348445.
The product of its digits is 50388480, while the sum is 55.
Adding to 51333244663663 its reverse (36636644233315), we get a palindrome (87969888896978).
The spelling of 51333244663663 in words is "fifty-one trillion, three hundred thirty-three billion, two hundred forty-four million, six hundred sixty-three thousand, six hundred sixty-three".
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