5133433013133 has 4 divisors (see below), whose sum is σ = 6844577350848. Its totient is φ = 3422288675420.

The previous prime is 5133433013131. The next prime is 5133433013179. The reversal of 5133433013133 is 3313103343315.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5133433013133 - 2¹ = 5133433013131 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5133433013094 and 5133433013103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5133433013131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 855572168853 + ... + 855572168858.

It is an arithmetic number, because the mean of its divisors is an integer number (1711144337712).

Almost surely, 2^{5133433013133} is an apocalyptic number.

It is an amenable number.

5133433013133 is a deficient number, since it is larger than the sum of its proper divisors (1711144337715).

5133433013133 is a wasteful number, since it uses less digits than its factorization.

5133433013133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1711144337714.

The product of its (nonzero) digits is 43740, while the sum is 33.

Adding to 5133433013133 its reverse (3313103343315), we get a palindrome (8446536356448).

The spelling of 5133433013133 in words is "five trillion, one hundred thirty-three billion, four hundred thirty-three million, thirteen thousand, one hundred thirty-three".