Base | Representation |
---|---|
bin | 1110111100010010010… |
… | …10000011001100001011 |
3 | 1211002011212212002122001 |
4 | 13132021022003030023 |
5 | 31402421432040243 |
6 | 1031504223211431 |
7 | 52043404610035 |
oct | 7361112031413 |
9 | 1732155762561 |
10 | 513402221323 |
11 | 188807195772 |
12 | 83601446b77 |
13 | 3954b95b154 |
14 | 1abc5170c55 |
15 | d54c536a4d |
hex | 778928330b |
513402221323 has 4 divisors (see below), whose sum is σ = 514027559808. Its totient is φ = 512776882840.
The previous prime is 513402221309. The next prime is 513402221347. The reversal of 513402221323 is 323122204315.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 513402221323 - 25 = 513402221291 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 513402221291 and 513402221300.
It is not an unprimeable number, because it can be changed into a prime (513402221303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 312668011 + ... + 312669652.
It is an arithmetic number, because the mean of its divisors is an integer number (128506889952).
Almost surely, 2513402221323 is an apocalyptic number.
513402221323 is a deficient number, since it is larger than the sum of its proper divisors (625338485).
513402221323 is an equidigital number, since it uses as much as digits as its factorization.
513402221323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 625338484.
The product of its (nonzero) digits is 8640, while the sum is 28.
Adding to 513402221323 its reverse (323122204315), we get a palindrome (836524425638).
The spelling of 513402221323 in words is "five hundred thirteen billion, four hundred two million, two hundred twenty-one thousand, three hundred twenty-three".
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