Base | Representation |
---|---|
bin | 10111010110001100111011… |
… | …00000110100001111000111 |
3 | 20201210002111211020101112020 |
4 | 23223012131200310033013 |
5 | 23212130102444331232 |
6 | 301105240440254223 |
7 | 13546135433463156 |
oct | 1353063540641707 |
9 | 221702454211466 |
10 | 51340386714567 |
11 | 153a437694a735 |
12 | 591213b771373 |
13 | 22854baa3c152 |
14 | c96c6086759d |
15 | 5e07344a8e2c |
hex | 2eb19d8343c7 |
51340386714567 has 4 divisors (see below), whose sum is σ = 68453848952760. Its totient is φ = 34226924476376.
The previous prime is 51340386714523. The next prime is 51340386714571. The reversal of 51340386714567 is 76541768304315.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51340386714567 - 232 = 51336091747271 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 51340386714567.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51340386714167) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8556731119092 + ... + 8556731119097.
It is an arithmetic number, because the mean of its divisors is an integer number (17113462238190).
Almost surely, 251340386714567 is an apocalyptic number.
51340386714567 is a deficient number, since it is larger than the sum of its proper divisors (17113462238193).
51340386714567 is a wasteful number, since it uses less digits than its factorization.
51340386714567 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17113462238192.
The product of its (nonzero) digits is 50803200, while the sum is 60.
The spelling of 51340386714567 in words is "fifty-one trillion, three hundred forty billion, three hundred eighty-six million, seven hundred fourteen thousand, five hundred sixty-seven".
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