Base | Representation |
---|---|
bin | 10111010110010001110010… |
… | …10111000100011011001011 |
3 | 20201210100021001020102200111 |
4 | 23223020321113010123023 |
5 | 23212200431324431011 |
6 | 301110352122215151 |
7 | 13546260303130552 |
oct | 1353107127043313 |
9 | 221710231212614 |
10 | 51343001405131 |
11 | 153a5498869427 |
12 | 591274b3544b7 |
13 | 2285816656927 |
14 | c9702bc10d99 |
15 | 5e0838cdc121 |
hex | 2eb2395c46cb |
51343001405131 has 32 divisors (see below), whose sum is σ = 58041124024320. Its totient is φ = 45126376243200.
The previous prime is 51343001405107. The next prime is 51343001405153. The reversal of 51343001405131 is 13150410034315.
It is a cyclic number.
It is not a de Polignac number, because 51343001405131 - 29 = 51343001404619 is a prime.
It is a super-2 number, since 2×513430014051312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51343001405093 and 51343001405102.
It is not an unprimeable number, because it can be changed into a prime (51343001405431) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 125261835 + ... + 125671051.
It is an arithmetic number, because the mean of its divisors is an integer number (1813785125760).
Almost surely, 251343001405131 is an apocalyptic number.
51343001405131 is a deficient number, since it is larger than the sum of its proper divisors (6698122619189).
51343001405131 is a wasteful number, since it uses less digits than its factorization.
51343001405131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 414795.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 51343001405131 its reverse (13150410034315), we get a palindrome (64493411439446).
The spelling of 51343001405131 in words is "fifty-one trillion, three hundred forty-three billion, one million, four hundred five thousand, one hundred thirty-one".
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