Base | Representation |
---|---|
bin | 10111010110010001111001… |
… | …00101011110100111000111 |
3 | 20201210100101211001110011201 |
4 | 23223020330211132213013 |
5 | 23212201034202422210 |
6 | 301110401334043331 |
7 | 13546261531060534 |
oct | 1353107445364707 |
9 | 221710354043151 |
10 | 51343055514055 |
11 | 153a5516366248 |
12 | 59127654a9547 |
13 | 2285824920346 |
14 | c97035097d8b |
15 | 5e083d92953a |
hex | 2eb23c95e9c7 |
51343055514055 has 16 divisors (see below), whose sum is σ = 62051263761600. Its totient is φ = 40781611613952.
The previous prime is 51343055514019. The next prime is 51343055514103. The reversal of 51343055514055 is 55041555034315.
It is a cyclic number.
It is not a de Polignac number, because 51343055514055 - 29 = 51343055513543 is a prime.
It is a super-2 number, since 2×513430555140552 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51343055513996 and 51343055514014.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12725739 + ... + 16267468.
It is an arithmetic number, because the mean of its divisors is an integer number (3878203985100).
Almost surely, 251343055514055 is an apocalyptic number.
51343055514055 is a deficient number, since it is larger than the sum of its proper divisors (10708208247545).
51343055514055 is a wasteful number, since it uses less digits than its factorization.
51343055514055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28995738.
The product of its (nonzero) digits is 2250000, while the sum is 46.
The spelling of 51343055514055 in words is "fifty-one trillion, three hundred forty-three billion, fifty-five million, five hundred fourteen thousand, fifty-five".
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