51343140105041 has 4 divisors (see below), whose sum is σ = 51386614399284. Its totient is φ = 51299665810800.

The previous prime is 51343140105011. The next prime is 51343140105091. The reversal of 51343140105041 is 14050104134315.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 26194128720400 + 25149011384641 = 5118020^2 + 5014879^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-51343140105041 is a prime.

It is a super-2 number, since 2×51343140105041² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 51343140104989 and 51343140105007.

It is not an unprimeable number, because it can be changed into a prime (51343140105011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21737145350 + ... + 21737147711.

It is an arithmetic number, because the mean of its divisors is an integer number (12846653599821).

Almost surely, 2^{51343140105041} is an apocalyptic number.

It is an amenable number.

51343140105041 is a deficient number, since it is larger than the sum of its proper divisors (43474294243).

51343140105041 is a wasteful number, since it uses less digits than its factorization.

51343140105041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43474294242.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 51343140105041 its reverse (14050104134315), we get a palindrome (65393244239356).

The spelling of 51343140105041 in words is "fifty-one trillion, three hundred forty-three billion, one hundred forty million, one hundred five thousand, forty-one".