51344015441 has 4 divisors (see below), whose sum is σ = 52731691572. Its totient is φ = 49956339312.

The previous prime is 51344015413. The next prime is 51344015483. The reversal of 51344015441 is 14451044315.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 14451044315 = 5 ⋅2890208863.

It can be written as a sum of positive squares in 2 ways, for example, as 31872603841 + 19471411600 = 178529^2 + 139540^2 .

It is a cyclic number.

It is not a de Polignac number, because 51344015441 - 2³⁴ = 34164146257 is a prime.

It is a super-3 number, since 3×51344015441³ (a number of 33 digits) contains 333 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 51344015398 and 51344015407.

It is not an unprimeable number, because it can be changed into a prime (51344015141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 693838010 + ... + 693838083.

It is an arithmetic number, because the mean of its divisors is an integer number (13182922893).

Almost surely, 2^51344015441 is an apocalyptic number.

It is an amenable number.

51344015441 is a deficient number, since it is larger than the sum of its proper divisors (1387676131).

51344015441 is a wasteful number, since it uses less digits than its factorization.

51344015441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1387676130.

The product of its (nonzero) digits is 19200, while the sum is 32.

Adding to 51344015441 its reverse (14451044315), we get a palindrome (65795059756).

The spelling of 51344015441 in words is "fifty-one billion, three hundred forty-four million, fifteen thousand, four hundred forty-one".