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5134702081 = 31975872909
BaseRepresentation
bin1001100100000110…
…10101011000000001
3111020211211220002011
410302003111120001
541003440431311
62205302252521
7241146150625
oct46203253001
914224756064
105134702081
1121a5450743
12bb3727141
1363aa32672
14369d27185
15200bb3321
hex1320d5601

5134702081 has 16 divisors (see below), whose sum is σ = 5365946880. Its totient is φ = 4907773440.

The previous prime is 5134702061. The next prime is 5134702093. The reversal of 5134702081 is 1802074315.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5134702081 is a prime.

It is a super-2 number, since 2×51347020812 = 52730330921251461122, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (31).

It is not an unprimeable number, because it can be changed into a prime (5134702061) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1763655 + ... + 1766563.

It is an arithmetic number, because the mean of its divisors is an integer number (335371680).

Almost surely, 25134702081 is an apocalyptic number.

It is an amenable number.

5134702081 is a deficient number, since it is larger than the sum of its proper divisors (231244799).

5134702081 is a wasteful number, since it uses less digits than its factorization.

5134702081 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3624.

The product of its (nonzero) digits is 6720, while the sum is 31.

The square root of 5134702081 is about 71656.8355497227. The cubic root of 5134702081 is about 1725.1958980490.

Adding to 5134702081 its reverse (1802074315), we get a palindrome (6936776396).

The spelling of 5134702081 in words is "five billion, one hundred thirty-four million, seven hundred two thousand, eighty-one".

Divisors: 1 31 97 587 2909 3007 18197 56939 90179 282173 1707583 1765109 8747363 52935073 165635551 5134702081