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5135205462253 = 11447448607099
BaseRepresentation
bin100101010111010001000…
…0110001111000011101101
3200011220212022001020211021
41022232202012033003231
51133113400044243003
614531025242454141
71040002115141236
oct112564206170355
920156768036737
105135205462253
1116aa912677509
126ab2a1b04351
132b332b544c79
1413a78c31808d
158d8a25742bd
hex4aba218f0ed

5135205462253 has 4 divisors (see below), whose sum is σ = 5135654080800. Its totient is φ = 5134756843708.

The previous prime is 5135205462251. The next prime is 5135205462301. The reversal of 5135205462253 is 3522645025315.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5135205462253 - 21 = 5135205462251 is a prime.

It is a super-3 number, since 3×51352054622533 (a number of 39 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5135205462251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224292103 + ... + 224314996.

It is an arithmetic number, because the mean of its divisors is an integer number (1283913520200).

Almost surely, 25135205462253 is an apocalyptic number.

It is an amenable number.

5135205462253 is a deficient number, since it is larger than the sum of its proper divisors (448618547).

5135205462253 is a wasteful number, since it uses less digits than its factorization.

5135205462253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 448618546.

The product of its (nonzero) digits is 1080000, while the sum is 43.

The spelling of 5135205462253 in words is "five trillion, one hundred thirty-five billion, two hundred five million, four hundred sixty-two thousand, two hundred fifty-three".

Divisors: 1 11447 448607099 5135205462253