Base | Representation |
---|---|
bin | 10111010110111001111000… |
… | …00010010101000100110001 |
3 | 20201212101210210102001100202 |
4 | 23223130330002111010301 |
5 | 23213024014402331213 |
6 | 301124311340524545 |
7 | 13550651500622141 |
oct | 1353347402250461 |
9 | 221771723361322 |
10 | 51364521136433 |
11 | 1540363112502a |
12 | 5916956250755 |
13 | 2287865b4184b |
14 | c980adc94921 |
15 | 5e119819db58 |
hex | 2eb73c095131 |
51364521136433 has 8 divisors (see below), whose sum is σ = 52460074208640. Its totient is φ = 50269080186000.
The previous prime is 51364521136417. The next prime is 51364521136459. The reversal of 51364521136433 is 33463112546315.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 51364521136433 - 24 = 51364521136417 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (47).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51364521136133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27104123 + ... + 28937216.
It is an arithmetic number, because the mean of its divisors is an integer number (6557509276080).
Almost surely, 251364521136433 is an apocalyptic number.
It is an amenable number.
51364521136433 is a deficient number, since it is larger than the sum of its proper divisors (1095553072207).
51364521136433 is a wasteful number, since it uses less digits than its factorization.
51364521136433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56060887.
The product of its digits is 2332800, while the sum is 47.
The spelling of 51364521136433 in words is "fifty-one trillion, three hundred sixty-four billion, five hundred twenty-one million, one hundred thirty-six thousand, four hundred thirty-three".
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