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51365473053 = 317121824351
BaseRepresentation
bin101111110101100111…
…101110101100011101
311220120202012101111220
4233311213232230131
51320144030114203
635332540203553
73465612213516
oct576547565435
9156522171456
1051365473053
111a86951a184
129b562395b9
134ac791cb4b
1426b3c15a0d
1515096b9653
hexbf59eeb1d

51365473053 has 4 divisors (see below), whose sum is σ = 68487297408. Its totient is φ = 34243648700.

The previous prime is 51365473037. The next prime is 51365473067. The reversal of 51365473053 is 35037456315.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51365473053 - 24 = 51365473037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 51365472996 and 51365473014.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51365473013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8560912173 + ... + 8560912178.

It is an arithmetic number, because the mean of its divisors is an integer number (17121824352).

Almost surely, 251365473053 is an apocalyptic number.

It is an amenable number.

51365473053 is a deficient number, since it is larger than the sum of its proper divisors (17121824355).

51365473053 is a wasteful number, since it uses less digits than its factorization.

51365473053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17121824354.

The product of its (nonzero) digits is 567000, while the sum is 42.

The spelling of 51365473053 in words is "fifty-one billion, three hundred sixty-five million, four hundred seventy-three thousand, fifty-three".

Divisors: 1 3 17121824351 51365473053