Base | Representation |
---|---|
bin | 10111010111000001001010… |
… | …10101000110110100111111 |
3 | 20201212202220120022112210111 |
4 | 23223200211111012310333 |
5 | 23213110023344301033 |
6 | 301130155555450451 |
7 | 13551150465320626 |
oct | 1353404525066477 |
9 | 221782816275714 |
10 | 51368435150143 |
11 | 1540525a519501 |
12 | 5917668bb6a27 |
13 | 228803a9b81a7 |
14 | c98361a246bd |
15 | 5e1326adb7cd |
hex | 2eb825546d3f |
51368435150143 has 4 divisors (see below), whose sum is σ = 52756771235320. Its totient is φ = 49980099064968.
The previous prime is 51368435150111. The next prime is 51368435150161. The reversal of 51368435150143 is 34105153486315.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51368435150143 - 25 = 51368435150111 is a prime.
It is a super-2 number, since 2×513684351501432 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51368435150843) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 694168042533 + ... + 694168042606.
It is an arithmetic number, because the mean of its divisors is an integer number (13189192808830).
Almost surely, 251368435150143 is an apocalyptic number.
51368435150143 is a deficient number, since it is larger than the sum of its proper divisors (1388336085177).
51368435150143 is a wasteful number, since it uses less digits than its factorization.
51368435150143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1388336085176.
The product of its (nonzero) digits is 2592000, while the sum is 49.
The spelling of 51368435150143 in words is "fifty-one trillion, three hundred sixty-eight billion, four hundred thirty-five million, one hundred fifty thousand, one hundred forty-three".
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