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5138741 = 15713271
BaseRepresentation
bin10011100110100100110101
3100200002000202
4103212210311
52303414431
6302050245
761451516
oct23464465
910602022
105138741
11299a8a3
121879985
1310abc9a
1497aa0d
156b78cb
hex4e6935

5138741 has 4 divisors (see below), whose sum is σ = 5143584. Its totient is φ = 5133900.

The previous prime is 5138719. The next prime is 5138747. The reversal of 5138741 is 1478315.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 1478315 = 5295663.

It is a cyclic number.

It is not a de Polignac number, because 5138741 - 26 = 5138677 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5138747) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65 + ... + 3206.

It is an arithmetic number, because the mean of its divisors is an integer number (1285896).

Almost surely, 25138741 is an apocalyptic number.

It is an amenable number.

5138741 is a deficient number, since it is larger than the sum of its proper divisors (4843).

5138741 is a wasteful number, since it uses less digits than its factorization.

5138741 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4842.

The product of its digits is 3360, while the sum is 29.

The square root of 5138741 is about 2266.8791321992. The cubic root of 5138741 is about 172.5648121645.

It can be divided in two parts, 51 and 38741, that multiplied together give a palindrome (1975791).

The spelling of 5138741 in words is "five million, one hundred thirty-eight thousand, seven hundred forty-one".

Divisors: 1 1571 3271 5138741