Base | Representation |
---|---|
bin | 1110111101011011011… |
… | …00110110101111001011 |
3 | 1211010202121111222221111 |
4 | 13132231230312233023 |
5 | 31410200410401011 |
6 | 1032045124151151 |
7 | 52064531113510 |
oct | 7365554665713 |
9 | 1733677458844 |
10 | 514015325131 |
11 | 188aa1283730 |
12 | 837528384b7 |
13 | 39618994279 |
14 | 1ac42769307 |
15 | d586292121 |
hex | 77adb36bcb |
514015325131 has 32 divisors (see below), whose sum is σ = 674631410688. Its totient is φ = 379726448640.
The previous prime is 514015325093. The next prime is 514015325141. The reversal of 514015325131 is 131523510415.
It is not a de Polignac number, because 514015325131 - 213 = 514015316939 is a prime.
It is a super-2 number, since 2×5140153251312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 514015325093 and 514015325102.
It is not an unprimeable number, because it can be changed into a prime (514015325141) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1084126 + ... + 1484371.
It is an arithmetic number, because the mean of its divisors is an integer number (21082231584).
Almost surely, 2514015325131 is an apocalyptic number.
514015325131 is a deficient number, since it is larger than the sum of its proper divisors (160616085557).
514015325131 is a wasteful number, since it uses less digits than its factorization.
514015325131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2568651.
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 514015325131 its reverse (131523510415), we get a palindrome (645538835546).
The spelling of 514015325131 in words is "five hundred fourteen billion, fifteen million, three hundred twenty-five thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •