Base | Representation |
---|---|
bin | 11110101000111… |
… | …111111101001011 |
3 | 1022211022011111221 |
4 | 132220333331023 |
5 | 2023100023303 |
6 | 123002102511 |
7 | 15511321312 |
oct | 3650777513 |
9 | 1284264457 |
10 | 514064203 |
11 | 2441a3054 |
12 | 1241aaa37 |
13 | 8266a803 |
14 | 4c3b7279 |
15 | 301e54bd |
hex | 1ea3ff4b |
514064203 has 4 divisors (see below), whose sum is σ = 514710000. Its totient is φ = 513418408.
The previous prime is 514064143. The next prime is 514064231. The reversal of 514064203 is 302460415.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 302460415 = 5 ⋅60492083.
It is a cyclic number.
It is not a de Polignac number, because 514064203 - 217 = 513933131 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (514064293) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 321703 + ... + 323296.
It is an arithmetic number, because the mean of its divisors is an integer number (128677500).
Almost surely, 2514064203 is an apocalyptic number.
514064203 is a deficient number, since it is larger than the sum of its proper divisors (645797).
514064203 is an equidigital number, since it uses as much as digits as its factorization.
514064203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 645796.
The product of its (nonzero) digits is 2880, while the sum is 25.
The square root of 514064203 is about 22672.9839897619. The cubic root of 514064203 is about 801.0736641412.
The spelling of 514064203 in words is "five hundred fourteen million, sixty-four thousand, two hundred three".
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