Base | Representation |
---|---|
bin | 1110111101110011001… |
… | …00000110000001101011 |
3 | 1211011021111000202200000 |
4 | 13132321210012001223 |
5 | 31411102333330201 |
6 | 1032120554114043 |
7 | 52102465620615 |
oct | 7367144060153 |
9 | 1734244022600 |
10 | 514214355051 |
11 | 189093663871 |
12 | 837a941b923 |
13 | 3964ac9bb57 |
14 | 1ac60d77db5 |
15 | d5989a8d86 |
hex | 77b990606b |
514214355051 has 48 divisors (see below), whose sum is σ = 782483520000. Its totient is φ = 337398486048.
The previous prime is 514214355049. The next prime is 514214355089. The reversal of 514214355051 is 150553412415.
514214355051 is a `hidden beast` number, since 5 + 1 + 4 + 2 + 143 + 5 + 505 + 1 = 666.
It is not a de Polignac number, because 514214355051 - 21 = 514214355049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 514214354997 and 514214355015.
It is not an unprimeable number, because it can be changed into a prime (514214355001) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 6043200 + ... + 6127698.
It is an arithmetic number, because the mean of its divisors is an integer number (16301740000).
Almost surely, 2514214355051 is an apocalyptic number.
514214355051 is a deficient number, since it is larger than the sum of its proper divisors (268269164949).
514214355051 is an equidigital number, since it uses as much as digits as its factorization.
514214355051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 84910 (or 84898 counting only the distinct ones).
The product of its (nonzero) digits is 60000, while the sum is 36.
Adding to 514214355051 its reverse (150553412415), we get a palindrome (664767767466).
The spelling of 514214355051 in words is "five hundred fourteen billion, two hundred fourteen million, three hundred fifty-five thousand, fifty-one".
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