Base | Representation |
---|---|
bin | 100101011010100010100… |
… | …1011010101000110000011 |
3 | 200012121000022002111110102 |
4 | 1022311011023111012003 |
5 | 1133222300012414303 |
6 | 14534151045153015 |
7 | 1040341261435265 |
oct | 112650513250603 |
9 | 20177008074412 |
10 | 5142236451203 |
11 | 17028a0467585 |
12 | 6b07246bb76b |
13 | 2b3bac0ab067 |
14 | 13ac5801db35 |
15 | 8db64960288 |
hex | 4ad452d5183 |
5142236451203 has 4 divisors (see below), whose sum is σ = 5169159155328. Its totient is φ = 5115313747080.
The previous prime is 5142236451197. The next prime is 5142236451283. The reversal of 5142236451203 is 3021546322415.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5142236451203 - 28 = 5142236450947 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5142236451283) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13461351776 + ... + 13461352157.
It is an arithmetic number, because the mean of its divisors is an integer number (1292289788832).
Almost surely, 25142236451203 is an apocalyptic number.
5142236451203 is a deficient number, since it is larger than the sum of its proper divisors (26922704125).
5142236451203 is a wasteful number, since it uses less digits than its factorization.
5142236451203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26922704124.
The product of its (nonzero) digits is 172800, while the sum is 38.
The spelling of 5142236451203 in words is "five trillion, one hundred forty-two billion, two hundred thirty-six million, four hundred fifty-one thousand, two hundred three".
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