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51431450341 = 192706918439
BaseRepresentation
bin101111111001100011…
…011010011011100101
311220202100100101100011
4233321203122123211
51320312422402331
635343254250221
73500343054235
oct577143323345
9156670311304
1051431450341
111a8a2792967
129b74356971
134b084b066b
1426bc8abcc5
15151039d3b1
hexbf98da6e5

51431450341 has 4 divisors (see below), whose sum is σ = 54138368800. Its totient is φ = 48724531884.

The previous prime is 51431450339. The next prime is 51431450347. The reversal of 51431450341 is 14305413415.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51431450341 - 21 = 51431450339 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51431450347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1353459201 + ... + 1353459238.

It is an arithmetic number, because the mean of its divisors is an integer number (13534592200).

Almost surely, 251431450341 is an apocalyptic number.

It is an amenable number.

51431450341 is a deficient number, since it is larger than the sum of its proper divisors (2706918459).

51431450341 is a wasteful number, since it uses less digits than its factorization.

51431450341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2706918458.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 51431450341 its reverse (14305413415), we get a palindrome (65736863756).

The spelling of 51431450341 in words is "fifty-one billion, four hundred thirty-one million, four hundred fifty thousand, three hundred forty-one".

Divisors: 1 19 2706918439 51431450341