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5143311561 = 31714437187
BaseRepresentation
bin1001100101001000…
…01011010011001001
3111021110001022001210
410302210023103021
541013141432221
62210211003333
7241312266303
oct46244132311
914243038053
105143311561
1121aa2a1113
12bb6599549
1363c75832b
1436b128973
15201814276
hex13290b4c9

5143311561 has 4 divisors (see below), whose sum is σ = 6857748752. Its totient is φ = 3428874372.

The previous prime is 5143311557. The next prime is 5143311599. The reversal of 5143311561 is 1651133415.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 5143311561 - 22 = 5143311557 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5143311541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 857218591 + ... + 857218596.

It is an arithmetic number, because the mean of its divisors is an integer number (1714437188).

Almost surely, 25143311561 is an apocalyptic number.

It is an amenable number.

5143311561 is a deficient number, since it is larger than the sum of its proper divisors (1714437191).

5143311561 is a wasteful number, since it uses less digits than its factorization.

5143311561 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1714437190.

The product of its digits is 5400, while the sum is 30.

The square root of 5143311561 is about 71716.8847692090. The cubic root of 5143311561 is about 1726.1595856260.

Adding to 5143311561 its reverse (1651133415), we get a palindrome (6794444976).

The spelling of 5143311561 in words is "five billion, one hundred forty-three million, three hundred eleven thousand, five hundred sixty-one".

Divisors: 1 3 1714437187 5143311561