514332708047 has 4 divisors (see below), whose sum is σ = 514334203440. Its totient is φ = 514331212656.

The previous prime is 514332708017. The next prime is 514332708059. The reversal of 514332708047 is 740807233415.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 740807233415 = 5 ⋅148161446683.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-514332708047 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 514332707989 and 514332708007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (514332708017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56654 + ... + 1015812.

It is an arithmetic number, because the mean of its divisors is an integer number (128583550860).

Almost surely, 2^514332708047 is an apocalyptic number.

514332708047 is a deficient number, since it is larger than the sum of its proper divisors (1495393).

514332708047 is an equidigital number, since it uses as much as digits as its factorization.

514332708047 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1495392.

The product of its (nonzero) digits is 564480, while the sum is 44.

The spelling of 514332708047 in words is "five hundred fourteen billion, three hundred thirty-two million, seven hundred eight thousand, forty-seven".