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5143403115141 = 33974318558451
BaseRepresentation
bin100101011011000101010…
…1101110011001010000101
3200012201000121101011111220
41022312022231303022011
51133232142144141031
614534502522550553
71040412216062004
oct112661255631205
920181017334456
105143403115141
111703339a74455
126b09ab368459
132b40369ccc55
1413ad28d52c3b
158dbd20b3596
hex4ad8ab73285

5143403115141 has 8 divisors (see below), whose sum is σ = 6875145055584. Its totient is φ = 3420298292400.

The previous prime is 5143403115133. The next prime is 5143403115163. The reversal of 5143403115141 is 1415113043415.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 5143403115141 - 23 = 5143403115133 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5143403115121) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2159278035 + ... + 2159280416.

It is an arithmetic number, because the mean of its divisors is an integer number (859393131948).

Almost surely, 25143403115141 is an apocalyptic number.

It is an amenable number.

5143403115141 is a deficient number, since it is larger than the sum of its proper divisors (1731741940443).

5143403115141 is a wasteful number, since it uses less digits than its factorization.

5143403115141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4318558851.

The product of its (nonzero) digits is 14400, while the sum is 33.

Adding to 5143403115141 its reverse (1415113043415), we get a palindrome (6558516158556).

The spelling of 5143403115141 in words is "five trillion, one hundred forty-three billion, four hundred three million, one hundred fifteen thousand, one hundred forty-one".

Divisors: 1 3 397 1191 4318558451 12955675353 1714467705047 5143403115141