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514351071349 = 3438114960329
BaseRepresentation
bin1110111110000011011…
…01101000000001110101
31211011122000021200011121
413133001231220001311
531411342333240344
61032142320303541
752106045653453
oct7370155500165
91734560250147
10514351071349
11189153852845
1283827171bb1
13396703c967b
141ac751a59d3
15d5a59b2684
hex77c1b68075

514351071349 has 4 divisors (see below), whose sum is σ = 514366066060. Its totient is φ = 514336076640.

The previous prime is 514351071347. The next prime is 514351071473. The reversal of 514351071349 is 943170153415.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 177030562500 + 337320508849 = 420750^2 + 580793^2 .

It is a cyclic number.

It is not a de Polignac number, because 514351071349 - 21 = 514351071347 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (514351071347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7445784 + ... + 7514545.

It is an arithmetic number, because the mean of its divisors is an integer number (128591516515).

Almost surely, 2514351071349 is an apocalyptic number.

It is an amenable number.

514351071349 is a deficient number, since it is larger than the sum of its proper divisors (14994711).

514351071349 is a wasteful number, since it uses less digits than its factorization.

514351071349 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14994710.

The product of its (nonzero) digits is 226800, while the sum is 43.

The spelling of 514351071349 in words is "five hundred fourteen billion, three hundred fifty-one million, seventy-one thousand, three hundred forty-nine".

Divisors: 1 34381 14960329 514351071349