Base | Representation |
---|---|
bin | 100101011011010111110… |
… | …0001000101110010000111 |
3 | 200012202121122011121221200 |
4 | 1022312233201011302013 |
5 | 1133234423224244201 |
6 | 14535044100313543 |
7 | 1040433424105044 |
oct | 112665741056207 |
9 | 20182548147850 |
10 | 5144020540551 |
11 | 1703626544292 |
12 | 6b0b420a28b3 |
13 | 2b41048ba129 |
14 | 13ad86d541cb |
15 | 8dc1b3c4386 |
hex | 4adaf845c87 |
5144020540551 has 12 divisors (see below), whose sum is σ = 7450172143128. Its totient is φ = 3420153064944.
The previous prime is 5144020540523. The next prime is 5144020540567. The reversal of 5144020540551 is 1550450204415.
5144020540551 is a `hidden beast` number, since 5 + 1 + 4 + 40 + 20 + 5 + 40 + 551 = 666.
It is not a de Polignac number, because 5144020540551 - 227 = 5143886322823 is a prime.
It is a super-2 number, since 2×51440205405512 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5144020540951) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 766159965 + ... + 766166678.
It is an arithmetic number, because the mean of its divisors is an integer number (620847678594).
Almost surely, 25144020540551 is an apocalyptic number.
5144020540551 is a deficient number, since it is larger than the sum of its proper divisors (2306151602577).
5144020540551 is a wasteful number, since it uses less digits than its factorization.
5144020540551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1532327022 (or 1532327019 counting only the distinct ones).
The product of its (nonzero) digits is 80000, while the sum is 36.
Adding to 5144020540551 its reverse (1550450204415), we get a palindrome (6694470744966).
The spelling of 5144020540551 in words is "five trillion, one hundred forty-four billion, twenty million, five hundred forty thousand, five hundred fifty-one".
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