514442113124201 has 4 divisors (see below), whose sum is σ = 525387689999232. Its totient is φ = 503496536249172.

The previous prime is 514442113124183. The next prime is 514442113124207. The reversal of 514442113124201 is 102421311244415.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-514442113124201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (514442113124207) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5472788437445 + ... + 5472788437538.

It is an arithmetic number, because the mean of its divisors is an integer number (131346922499808).

Almost surely, 2^{514442113124201} is an apocalyptic number.

It is an amenable number.

514442113124201 is a deficient number, since it is larger than the sum of its proper divisors (10945576875031).

514442113124201 is a wasteful number, since it uses less digits than its factorization.

514442113124201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10945576875030.

The product of its (nonzero) digits is 30720, while the sum is 35.

Adding to 514442113124201 its reverse (102421311244415), we get a palindrome (616863424368616).

The spelling of 514442113124201 in words is "five hundred fourteen trillion, four hundred forty-two billion, one hundred thirteen million, one hundred twenty-four thousand, two hundred one".