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5145104041 = 71126074503
BaseRepresentation
bin1001100101010110…
…00000111010101001
3111021120102100212221
410302223000322221
541014121312131
62210313234041
7241333443220
oct46253007251
914246370787
105145104041
112200305900
12bb7102921
1363cc3517c
1436b473cb7
15201a6a411
hex132ac0ea9

5145104041 has 12 divisors (see below), whose sum is σ = 6463272256. Its totient is φ = 4009171320.

The previous prime is 5145104033. The next prime is 5145104047. The reversal of 5145104041 is 1404015415.

It is not a de Polignac number, because 5145104041 - 23 = 5145104033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5145103997 and 5145104015.

It is not an unprimeable number, because it can be changed into a prime (5145104047) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3036405 + ... + 3038098.

Almost surely, 25145104041 is an apocalyptic number.

It is an amenable number.

5145104041 is a deficient number, since it is larger than the sum of its proper divisors (1318168215).

5145104041 is a wasteful number, since it uses less digits than its factorization.

5145104041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6074532 (or 6074521 counting only the distinct ones).

The product of its (nonzero) digits is 1600, while the sum is 25.

The square root of 5145104041 is about 71729.3805981900. The cubic root of 5145104041 is about 1726.3600885593.

Adding to 5145104041 its reverse (1404015415), we get a palindrome (6549119456).

The spelling of 5145104041 in words is "five billion, one hundred forty-five million, one hundred four thousand, forty-one".

Divisors: 1 7 11 77 121 847 6074503 42521521 66819533 467736731 735014863 5145104041