Base | Representation |
---|---|
bin | 100101011011111011101… |
… | …0001000101011011010111 |
3 | 200012212201112021011102211 |
4 | 1022313313101011123113 |
5 | 1133244404410214333 |
6 | 14535403341214251 |
7 | 1040505311660344 |
oct | 112676721053327 |
9 | 20185645234384 |
10 | 5145224304343 |
11 | 1704093a908a2 |
12 | 6b1219261387 |
13 | 2b42670cb7b6 |
14 | 13b05cb837cb |
15 | 8dc8be04ecd |
hex | 4adf74456d7 |
5145224304343 has 4 divisors (see below), whose sum is σ = 5147832124008. Its totient is φ = 5142616484680.
The previous prime is 5145224304307. The next prime is 5145224304359. The reversal of 5145224304343 is 3434034225415.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5145224304343 - 213 = 5145224296151 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5145224304296 and 5145224304305.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5145224307343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1303906873 + ... + 1303910818.
It is an arithmetic number, because the mean of its divisors is an integer number (1286958031002).
Almost surely, 25145224304343 is an apocalyptic number.
5145224304343 is a deficient number, since it is larger than the sum of its proper divisors (2607819665).
5145224304343 is a wasteful number, since it uses less digits than its factorization.
5145224304343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2607819664.
The product of its (nonzero) digits is 691200, while the sum is 40.
Adding to 5145224304343 its reverse (3434034225415), we get a palindrome (8579258529758).
The spelling of 5145224304343 in words is "five trillion, one hundred forty-five billion, two hundred twenty-four million, three hundred four thousand, three hundred forty-three".
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