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51461538447041 = 445431155322687
BaseRepresentation
bin10111011001101110100101…
…01101111111111011000001
320202012200020002121001221222
423230313102231333323001
523221121212320301131
6301241034314324425
713560654616303202
oct1354672255777301
9222180202531858
1051461538447041
1115440796943478
125931711129715
132293a5771b008
14c9ca74b375a9
155e397561387b
hex2ecdd2b7fec1

51461538447041 has 4 divisors (see below), whose sum is σ = 51462693814272. Its totient is φ = 51460383079812.

The previous prime is 51461538447029. The next prime is 51461538447049. The reversal of 51461538447041 is 14074483516415.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51461538447041 - 218 = 51461538184897 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51461538447049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 577616801 + ... + 577705886.

It is an arithmetic number, because the mean of its divisors is an integer number (12865673453568).

Almost surely, 251461538447041 is an apocalyptic number.

It is an amenable number.

51461538447041 is a deficient number, since it is larger than the sum of its proper divisors (1155367231).

51461538447041 is a wasteful number, since it uses less digits than its factorization.

51461538447041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1155367230.

The product of its (nonzero) digits is 6451200, while the sum is 53.

The spelling of 51461538447041 in words is "fifty-one trillion, four hundred sixty-one billion, five hundred thirty-eight million, four hundred forty-seven thousand, forty-one".

Divisors: 1 44543 1155322687 51461538447041