Base | Representation |
---|---|
bin | 10111011010000110101100… |
… | …10001000011011100011111 |
3 | 20202020220122012210220010021 |
4 | 23231003112101003130133 |
5 | 23221324220103320142 |
6 | 301251015002253011 |
7 | 13561623446134606 |
oct | 1355032621033437 |
9 | 222226565726107 |
10 | 51474482870047 |
11 | 15446229709026 |
12 | 59341241b7167 |
13 | 229503b431003 |
14 | c9d541d56a3d |
15 | 5e3e81c38267 |
hex | 2ed0d644371f |
51474482870047 has 4 divisors (see below), whose sum is σ = 52865685109816. Its totient is φ = 50083280630280.
The previous prime is 51474482870029. The next prime is 51474482870081. The reversal of 51474482870047 is 74007828447415.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51474482870047 - 231 = 51472335386399 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51474482870087) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 695601119829 + ... + 695601119902.
It is an arithmetic number, because the mean of its divisors is an integer number (13216421277454).
Almost surely, 251474482870047 is an apocalyptic number.
51474482870047 is a deficient number, since it is larger than the sum of its proper divisors (1391202239769).
51474482870047 is a wasteful number, since it uses less digits than its factorization.
51474482870047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1391202239768.
The product of its (nonzero) digits is 56197120, while the sum is 61.
The spelling of 51474482870047 in words is "fifty-one trillion, four hundred seventy-four billion, four hundred eighty-two million, eight hundred seventy thousand, forty-seven".
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