Base | Representation |
---|---|
bin | 100101011110001110001… |
… | …1101010101110000100011 |
3 | 200020100102100010001100021 |
4 | 1022330130131111300203 |
5 | 1133334443132210001 |
6 | 14541535415134311 |
7 | 1041041231153311 |
oct | 112743435256043 |
9 | 20210370101307 |
10 | 5150143241251 |
11 | 1706188660a08 |
12 | 6b2170674397 |
13 | 2b486c217158 |
14 | 13b3a81830b1 |
15 | 8de78b97ba1 |
hex | 4af1c755c23 |
5150143241251 has 4 divisors (see below), whose sum is σ = 5150165625000. Its totient is φ = 5150120857504.
The previous prime is 5150143241231. The next prime is 5150143241263. The reversal of 5150143241251 is 1521423410515.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5150143241251 - 229 = 5149606370339 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5150143241231) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10843126 + ... + 11308123.
It is an arithmetic number, because the mean of its divisors is an integer number (1287541406250).
Almost surely, 25150143241251 is an apocalyptic number.
5150143241251 is a deficient number, since it is larger than the sum of its proper divisors (22383749).
5150143241251 is a wasteful number, since it uses less digits than its factorization.
5150143241251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22383748.
The product of its (nonzero) digits is 24000, while the sum is 34.
Adding to 5150143241251 its reverse (1521423410515), we get a palindrome (6671566651766).
The spelling of 5150143241251 in words is "five trillion, one hundred fifty billion, one hundred forty-three million, two hundred forty-one thousand, two hundred fifty-one".
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