Base | Representation |
---|---|
bin | 101111111110010111… |
… | …100101000101100101 |
3 | 11220221222100122011011 |
4 | 233332113211011211 |
5 | 1320444112444331 |
6 | 35355301542221 |
7 | 3502343524141 |
oct | 577627450545 |
9 | 156858318134 |
10 | 51512234341 |
11 | 1a93434a0a7 |
12 | 9b97414971 |
13 | 4b1c156849 |
14 | 26c94da221 |
15 | 15175093b1 |
hex | bfe5e5165 |
51512234341 has 4 divisors (see below), whose sum is σ = 51513024384. Its totient is φ = 51511444300.
The previous prime is 51512234329. The next prime is 51512234413. The reversal of 51512234341 is 14343221515.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 51512234341 - 225 = 51478679909 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51512534341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 287455 + ... + 430876.
It is an arithmetic number, because the mean of its divisors is an integer number (12878256096).
Almost surely, 251512234341 is an apocalyptic number.
It is an amenable number.
51512234341 is a deficient number, since it is larger than the sum of its proper divisors (790043).
51512234341 is an equidigital number, since it uses as much as digits as its factorization.
51512234341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 790042.
The product of its digits is 14400, while the sum is 31.
Adding to 51512234341 its reverse (14343221515), we get a palindrome (65855455856).
The spelling of 51512234341 in words is "fifty-one billion, five hundred twelve million, two hundred thirty-four thousand, three hundred forty-one".
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