Base | Representation |
---|---|
bin | 101111111110111010… |
… | …100010111000010111 |
3 | 11220222121121022112201 |
4 | 233332322202320113 |
5 | 1321003434302333 |
6 | 35400230225331 |
7 | 3502514451160 |
oct | 577672427027 |
9 | 156877538481 |
10 | 51521400343 |
11 | 1a93953a706 |
12 | 9b9a4b5247 |
13 | 4b2101590a |
14 | 26ca804767 |
15 | 151821a17d |
hex | bfeea2e17 |
51521400343 has 8 divisors (see below), whose sum is σ = 60250940288. Its totient is φ = 43134195384.
The previous prime is 51521400341. The next prime is 51521400391. The reversal of 51521400343 is 34300412515.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 51521400343 - 21 = 51521400341 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51521400341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 85583421 + ... + 85584022.
It is an arithmetic number, because the mean of its divisors is an integer number (7531367536).
Almost surely, 251521400343 is an apocalyptic number.
51521400343 is a deficient number, since it is larger than the sum of its proper divisors (8729539945).
51521400343 is a wasteful number, since it uses less digits than its factorization.
51521400343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 171167493.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 51521400343 its reverse (34300412515), we get a palindrome (85821812858).
The spelling of 51521400343 in words is "fifty-one billion, five hundred twenty-one million, four hundred thousand, three hundred forty-three".
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