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51521400343 = 743171167443
BaseRepresentation
bin101111111110111010…
…100010111000010111
311220222121121022112201
4233332322202320113
51321003434302333
635400230225331
73502514451160
oct577672427027
9156877538481
1051521400343
111a93953a706
129b9a4b5247
134b2101590a
1426ca804767
15151821a17d
hexbfeea2e17

51521400343 has 8 divisors (see below), whose sum is σ = 60250940288. Its totient is φ = 43134195384.

The previous prime is 51521400341. The next prime is 51521400391. The reversal of 51521400343 is 34300412515.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 51521400343 - 21 = 51521400341 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51521400341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 85583421 + ... + 85584022.

It is an arithmetic number, because the mean of its divisors is an integer number (7531367536).

Almost surely, 251521400343 is an apocalyptic number.

51521400343 is a deficient number, since it is larger than the sum of its proper divisors (8729539945).

51521400343 is a wasteful number, since it uses less digits than its factorization.

51521400343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 171167493.

The product of its (nonzero) digits is 7200, while the sum is 28.

Adding to 51521400343 its reverse (34300412515), we get a palindrome (85821812858).

The spelling of 51521400343 in words is "fifty-one billion, five hundred twenty-one million, four hundred thousand, three hundred forty-three".

Divisors: 1 7 43 301 171167443 1198172101 7360200049 51521400343