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51531000433 = 1159161949043
BaseRepresentation
bin101111111111011111…
…001010101001110001
311221000021200001101121
4233333133022221301
51321013414003213
635401212102241
73502662163603
oct577737125161
9157007601347
1051531000433
111a9439a7370
129ba1764981
134b22cc7443
1426cbbc3173
151518eb488d
hexbff7caa71

51531000433 has 16 divisors (see below), whose sum is σ = 57204921600. Its totient is φ = 46022974480.

The previous prime is 51531000413. The next prime is 51531000473. The reversal of 51531000433 is 33400013515.

It is a cyclic number.

It is not a de Polignac number, because 51531000433 - 25 = 51531000401 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 51531000398 and 51531000407.

It is not an unprimeable number, because it can be changed into a prime (51531000413) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1026210 + ... + 1075252.

It is an arithmetic number, because the mean of its divisors is an integer number (3575307600).

Almost surely, 251531000433 is an apocalyptic number.

It is an amenable number.

51531000433 is a deficient number, since it is larger than the sum of its proper divisors (5673921167).

51531000433 is a wasteful number, since it uses less digits than its factorization.

51531000433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50732.

The product of its (nonzero) digits is 2700, while the sum is 25.

Adding to 51531000433 its reverse (33400013515), we get a palindrome (84931013948).

The spelling of 51531000433 in words is "fifty-one billion, five hundred thirty-one million, four hundred thirty-three", and thus it is an aban number.

Divisors: 1 11 59 649 1619 17809 49043 95521 539473 1050731 2893537 31828907 79400617 873406787 4684636403 51531000433