Base | Representation |
---|---|
bin | 1001100110011100… |
… | …11000000110001111 |
3 | 111022012212022220220 |
4 | 10303032120012033 |
5 | 41024004432111 |
6 | 2211244042423 |
7 | 241505312352 |
oct | 46316300617 |
9 | 14265768826 |
10 | 5154374031 |
11 | 2205567554 |
12 | bba233413 |
13 | 641b2c681 |
14 | 36c7a8299 |
15 | 20279be06 |
hex | 13339818f |
5154374031 has 4 divisors (see below), whose sum is σ = 6872498712. Its totient is φ = 3436249352.
The previous prime is 5154373997. The next prime is 5154374063. The reversal of 5154374031 is 1304734515.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5154374031 - 217 = 5154242959 is a prime.
It is a super-2 number, since 2×51543740312 = 53135143302894377922, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5154373983 and 5154374001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5154379031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 859062336 + ... + 859062341.
It is an arithmetic number, because the mean of its divisors is an integer number (1718124678).
Almost surely, 25154374031 is an apocalyptic number.
5154374031 is a deficient number, since it is larger than the sum of its proper divisors (1718124681).
5154374031 is a wasteful number, since it uses less digits than its factorization.
5154374031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1718124680.
The product of its (nonzero) digits is 25200, while the sum is 33.
The square root of 5154374031 is about 71793.9693219424. The cubic root of 5154374031 is about 1727.3962671028.
The spelling of 5154374031 in words is "five billion, one hundred fifty-four million, three hundred seventy-four thousand, thirty-one".
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