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51550430341 = 54794242103
BaseRepresentation
bin110000000000101001…
…010010010010000101
311221001122020012012211
4300000221102102011
51321033402232331
635403144343421
73503316266554
oct600051222205
9157048205184
1051550430341
111a953968343
129ba8174b71
134b2703b227
1426d05ddd9b
15151aa518b1
hexc00a52485

51550430341 has 4 divisors (see below), whose sum is σ = 51644672992. Its totient is φ = 51456187692.

The previous prime is 51550430333. The next prime is 51550430353. The reversal of 51550430341 is 14303405515.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51550430341 - 23 = 51550430333 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51550430941) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47120505 + ... + 47121598.

It is an arithmetic number, because the mean of its divisors is an integer number (12911168248).

Almost surely, 251550430341 is an apocalyptic number.

It is an amenable number.

51550430341 is a deficient number, since it is larger than the sum of its proper divisors (94242651).

51550430341 is an equidigital number, since it uses as much as digits as its factorization.

51550430341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 94242650.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 51550430341 its reverse (14303405515), we get a palindrome (65853835856).

The spelling of 51550430341 in words is "fifty-one billion, five hundred fifty million, four hundred thirty thousand, three hundred forty-one".

Divisors: 1 547 94242103 51550430341