Base | Representation |
---|---|
bin | 100101100000100110100… |
… | …1001010010010110101111 |
3 | 200020211121120212002112012 |
4 | 1023001031021102112233 |
5 | 1133430430242112221 |
6 | 14544142542431435 |
7 | 1041312011534063 |
oct | 113011511222657 |
9 | 20224546762465 |
10 | 5155255035311 |
11 | 17083710854a7 |
12 | 6b315859257b |
13 | 2b51a5288874 |
14 | 13b731025aa3 |
15 | 8e17783365b |
hex | 4b04d2525af |
5155255035311 has 4 divisors (see below), whose sum is σ = 5155283410992. Its totient is φ = 5155226659632.
The previous prime is 5155255035199. The next prime is 5155255035313. The reversal of 5155255035311 is 1135305525515.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5155255035311 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5155255035313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13913555 + ... + 14279268.
It is an arithmetic number, because the mean of its divisors is an integer number (1288820852748).
Almost surely, 25155255035311 is an apocalyptic number.
5155255035311 is a deficient number, since it is larger than the sum of its proper divisors (28375681).
5155255035311 is a wasteful number, since it uses less digits than its factorization.
5155255035311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28375680.
The product of its (nonzero) digits is 281250, while the sum is 41.
The spelling of 5155255035311 in words is "five trillion, one hundred fifty-five billion, two hundred fifty-five million, thirty-five thousand, three hundred eleven".
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