Base | Representation |
---|---|
bin | 110000000000110011… |
… | …001110000001000111 |
3 | 11221001211010111012011 |
4 | 300000303032001013 |
5 | 1321040034044221 |
6 | 35403320235051 |
7 | 3503350363402 |
oct | 600063160107 |
9 | 157054114164 |
10 | 51553034311 |
11 | 1a955386789 |
12 | 9ba900ba87 |
13 | 4b2774053c |
14 | 26d0abad39 |
15 | 151adb81e1 |
hex | c00cce047 |
51553034311 has 4 divisors (see below), whose sum is σ = 51553666000. Its totient is φ = 51552402624.
The previous prime is 51553034297. The next prime is 51553034339. The reversal of 51553034311 is 11343035515.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51553034311 - 215 = 51553001543 is a prime.
It is a super-2 number, since 2×515530343112 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51553034341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 171411 + ... + 363988.
It is an arithmetic number, because the mean of its divisors is an integer number (12888416500).
Almost surely, 251553034311 is an apocalyptic number.
51553034311 is a deficient number, since it is larger than the sum of its proper divisors (631689).
51553034311 is an equidigital number, since it uses as much as digits as its factorization.
51553034311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 631688.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 51553034311 its reverse (11343035515), we get a palindrome (62896069826).
The spelling of 51553034311 in words is "fifty-one billion, five hundred fifty-three million, thirty-four thousand, three hundred eleven".
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