Base | Representation |
---|---|
bin | 100101100000101110110… |
… | …1110100100001100000111 |
3 | 200020212022222100111220222 |
4 | 1023001131232210030013 |
5 | 1133432013002240033 |
6 | 14544230321414555 |
7 | 1041321630341453 |
oct | 113013556441407 |
9 | 20225288314828 |
10 | 5155533243143 |
11 | 17084a4125128 |
12 | 6b321579a45b |
13 | 2b521aac659a |
14 | 13b759d65663 |
15 | 8e191e8a598 |
hex | 4b05dba4307 |
5155533243143 has 4 divisors (see below), whose sum is σ = 5160124102008. Its totient is φ = 5150942384280.
The previous prime is 5155533243139. The next prime is 5155533243149. The reversal of 5155533243143 is 3413423355515.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5155533243143 - 22 = 5155533243139 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5155533243094 and 5155533243103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5155533243149) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2295427748 + ... + 2295429993.
It is an arithmetic number, because the mean of its divisors is an integer number (1290031025502).
Almost surely, 25155533243143 is an apocalyptic number.
5155533243143 is a deficient number, since it is larger than the sum of its proper divisors (4590858865).
5155533243143 is a wasteful number, since it uses less digits than its factorization.
5155533243143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4590858864.
The product of its digits is 1620000, while the sum is 44.
Adding to 5155533243143 its reverse (3413423355515), we get a palindrome (8568956598658).
The spelling of 5155533243143 in words is "five trillion, one hundred fifty-five billion, five hundred thirty-three million, two hundred forty-three thousand, one hundred forty-three".
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