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51651133141 = 137113767131
BaseRepresentation
bin110000000110101001…
…011011111011010101
311221022122201102111011
4300012221123323111
51321240142230031
635421143012221
73505651246666
oct600651337325
9157278642434
1051651133141
111a9a57998a3
12a015a3a071
134b41b6989a
1426ddb3536d
1515247e46b1
hexc06a5bed5

51651133141 has 4 divisors (see below), whose sum is σ = 51654913984. Its totient is φ = 51647352300.

The previous prime is 51651133109. The next prime is 51651133151. The reversal of 51651133141 is 14133115615.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51651133141 - 25 = 51651133109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51651133151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1869855 + ... + 1897276.

It is an arithmetic number, because the mean of its divisors is an integer number (12913728496).

Almost surely, 251651133141 is an apocalyptic number.

It is an amenable number.

51651133141 is a deficient number, since it is larger than the sum of its proper divisors (3780843).

51651133141 is a wasteful number, since it uses less digits than its factorization.

51651133141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3780842.

The product of its digits is 5400, while the sum is 31.

Adding to 51651133141 its reverse (14133115615), we get a palindrome (65784248756).

The spelling of 51651133141 in words is "fifty-one billion, six hundred fifty-one million, one hundred thirty-three thousand, one hundred forty-one".

Divisors: 1 13711 3767131 51651133141