Base | Representation |
---|---|
bin | 110000001010011110… |
… | …011000000001100001 |
3 | 11221111010112121002002 |
4 | 300022132120001201 |
5 | 1321403111424213 |
6 | 35431355133345 |
7 | 3510361105046 |
oct | 601236300141 |
9 | 157433477062 |
10 | 51715342433 |
11 | 1aa28a65227 |
12 | a033444255 |
13 | 4b5225b751 |
14 | 270848b1cd |
15 | 152a279658 |
hex | c0a798061 |
51715342433 has 4 divisors (see below), whose sum is σ = 51820669488. Its totient is φ = 51610015380.
The previous prime is 51715342423. The next prime is 51715342463. The reversal of 51715342433 is 33424351715.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 51715342433 - 24 = 51715342417 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51715342423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52662791 + ... + 52663772.
It is an arithmetic number, because the mean of its divisors is an integer number (12955167372).
Almost surely, 251715342433 is an apocalyptic number.
It is an amenable number.
51715342433 is a deficient number, since it is larger than the sum of its proper divisors (105327055).
51715342433 is a wasteful number, since it uses less digits than its factorization.
51715342433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 105327054.
The product of its digits is 151200, while the sum is 38.
The spelling of 51715342433 in words is "fifty-one billion, seven hundred fifteen million, three hundred forty-two thousand, four hundred thirty-three".
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