Base | Representation |
---|---|
bin | 110000001011000111… |
… | …010010010110101101 |
3 | 11221111212201110120121 |
4 | 300023013102112231 |
5 | 1321413333121432 |
6 | 35432421044541 |
7 | 3510551213254 |
oct | 601307222655 |
9 | 157455643517 |
10 | 51726067117 |
11 | 1aa3401a8aa |
12 | a036b56751 |
13 | 4b5454510a |
14 | 2709a7d79b |
15 | 152b197197 |
hex | c0b1d25ad |
51726067117 has 4 divisors (see below), whose sum is σ = 51736083136. Its totient is φ = 51716051100.
The previous prime is 51726067111. The next prime is 51726067121. The reversal of 51726067117 is 71176062715.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51726067117 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51726067111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5000259 + ... + 5010592.
It is an arithmetic number, because the mean of its divisors is an integer number (12934020784).
Almost surely, 251726067117 is an apocalyptic number.
It is an amenable number.
51726067117 is a deficient number, since it is larger than the sum of its proper divisors (10016019).
51726067117 is a wasteful number, since it uses less digits than its factorization.
51726067117 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10016018.
The product of its (nonzero) digits is 123480, while the sum is 43.
The spelling of 51726067117 in words is "fifty-one billion, seven hundred twenty-six million, sixty-seven thousand, one hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •